What are the domain and range of f(x) = |x – 3 | + 6? Domain: {x | x is all real numbers}Range: {y | y ≥ 6}Domain: {x | x ≥ 3}Range: {y | y ≥ 6}Domain: {x | x is all real numbers}Range: {y | y ≥ – 6}Domain: {x | x ≥ 3}Range: {y | y ≥ – 6}

The absolute value expression |x − 3| is defined for every real number x, so the domain is all real numbers. Since an absolute value is never negative, |x − 3| ≥ 0, and adding 6 gives f(x) ≥ 6. The minimum value, 6, occurs at x = 3, so the range is y ≥ 6, matching choice A.

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