Question 10 • (OC27) MATH COLL ALGEBRA-1200710-S1-Degele-VOL7006P
Set the function equal to 15: 4|x − 5| + 3 = 15. Subtract 3 and divide by 4 to get |x − 5| = 3, so x − 5 is either 3 or −3. Therefore x = 8 or x = 2, matching choice A, “x = 2, x = 8.”
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