A truck heading east has an initial velocity of 6 meters per second It accelerates at 2 the fraction with numerator m and denominator s squared for 12 seconds. What distance does the truck travel in the given time?

For constant acceleration, the distance is the initial-velocity distance plus the acceleration contribution: d = vt + ½at². Using v = 6 m/s, a = 2 m/s², and t = 12 s gives d = (6)(12) + ½(2)(12²) = 72 + 144 = 216 m. The correct choice is 216 m.

AI-written and checked against the verified answer.