Suppose the initial position of an object is zero, the starting velocity is 3 meters per second and the final velocity was 10 meters per second The object moves with constant acceleration. Which part of a velocity vs. time graph can be used to calculate the displacement of the object?
Answer
A
the area of the rectangle plus the area of the triangle under the line
B
the area of the rectangle under the line
C
the area of the rectangle plus the area of the triangle above the line
D
the area of the rectangle above the line
Explanation
Displacement is the area under a velocity-versus-time graph. Since the velocity rises from 3 m/s to 10 m/s at a constant rate, the area under the line consists of a rectangle with height 3 m/s and a triangle for the additional increase in velocity. Adding these areas gives the displacement, so the correct choice is the area of the rectangle plus the area of the triangle under the line.
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