What is the sum? the fraction with numerator 3 and denominator x squared minus 9 plus the fraction with numerator 5 and denominator x plus 3

Factor the first denominator: x² − 9 = (x + 3)(x − 3). To add the fractions, rewrite 5/(x + 3) with denominator (x + 3)(x − 3), giving 5(x − 3)/[(x + 3)(x − 3)]. The numerators add to 3 + 5(x − 3) = 5x − 12, so the sum is (5x − 12)/[(x + 3)(x − 3)], choice C.

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