Answers TX-Algebra II A Addition and Subtraction of PolynomialsQuestion 2

2

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Addition and Subtraction of Polynomials

Question 2 • TX-Algebra II A

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) = a2 + ab + ( b2)

Answer

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =:

2

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =:

9

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =:

-7

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