A bicycle wheel with diameter 16 inches rides over a screw in the street. The screw is on level ground before it punctures the bike’s tire. After the bike has moved forward another 56π inches, how high above the ground is the screw? Round to the nearest tenth of an inch.

The wheel’s circumference is πd = 16π inches, so traveling 56π inches makes it roll 56π ÷ 16π = 3.5 rotations. The screw starts at the bottom of the wheel; after three full rotations it is still at the bottom, and the extra half-turn carries it to the top. The top of a 16-inch-diameter wheel is 16 inches above the ground, so the answer is D, 16 inches.

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