Question 6 • *25-26 KCS21 Precalculus IC
The center is the midpoint of the diameter’s endpoints: ((−12 + −6)/2, (3 + −5)/2) = (−9, −1). The distance between the endpoints is √(6² + 8²) = 10, so the radius is 5. Using (x − h)² + (y − k)² = r² gives (x + 9)² + (y + 1)² = 25, which is choice A.
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