4
QuizMultiple Choice

Applications of Conics

Question 4 • *25-26 KCS21 Precalculus IC

An architect designed a lobby wall to have an embedded circular clock. The equation (x – 4)2 + (y – 7)2 = 1, with units in meters, represents the location of the clock relative to the bottom left corner of the wall. How high above the ground is the center of the clock?

Answer
A
1 m
B
4 m
C
7 m
D
8 m

Explanation

A circle in the form (x − h)² + (y − k)² = r² has its center at (h, k). Here the center is (4, 7), and the y-coordinate measures height above the ground, so the clock’s center is 7 m high. Choice C, 7 m, is correct.

AI-written and checked against the verified answer.

Previous
Next