Question 5 • *25-26 KCS21 Precalculus IC
The equation is in vertex form, y = –16(x – 1)² + 25. Since (x – 1)² is always zero or positive, multiplying it by –16 gives a value that is zero or negative, so the greatest height occurs when x = 1 and the squared term is zero. The maximum height is 25 feet, choice D.
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