Question 8 • Precalculus
The third side is 16 − 7 − 6 = 3 meters. The semiperimeter is 16 ÷ 2 = 8 meters, so Heron’s formula gives an area of √(8 × (8 − 7) × (8 − 6) × (8 − 3)) = √80 ≈ 8.94 square meters. Rounded to the nearest square meter, the area is 9 square meters, choice B.
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