Adding and Subtracting Radicals

Question 1

Solve: The solution is a =

Revolt · Accepted Answer

1/6

Question 2

How many extraneous solutions are there?zeroonetwo

Revolt · Accepted Answer

zero

Question 3

Name the extraneous solution(s) to the equation.x = 0x = 1x = 8x = 0, x = 1, and x = 8x = 1 and x = 8There are no extraneous

Revolt · Accepted Answer

There are no extraneous

Question 4

Solve and check The solution is c =

Revolt · Accepted Answer

14

Question 5

After multiplying each side of the equation by the LCD and simplifying, the resulting equation is 3x² – 20x + 12 = 03x² – 20x – 12 = 03x² + 20x + 12 = 03x² + 20x – 12 = 0.

Revolt · Accepted Answer

3x² + 20x + 12 = 0

Question 6

From least to greatest, the solutions are x = [___] and x = [___].

Revolt · Accepted Answer

Part 1: -8; -8, -4

Question 7

Question 9

Revolt · Accepted Answer

No. Although solving the equation gives a = -2, substituting -2 makes two denominators in the original equation equal to zero. So -2 is an extraneous solution, and the original equation has no solution.

Question 8

From least to greatest, the solutions are x = [___] and x = [___].

Revolt · Accepted Answer

-4

Question 9

Name the true solution(s) to the equation.x = 0x = 1x = 8x = 0, x = 1, and x = 8 x = 1 and x = 8There are no solutions.

Revolt · Accepted Answer

= 1 and x = 8; Selection 1: x = 1 and x = 8; Selection 2: x = 0

Adding and Subtracting Radicals Answers

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