AnswersAZ-Common Core Algebra II BChanges in Period and Phase Shift of Sine and Cosine Functions

Changes in Period and Phase Shift of Sine and Cosine Functions Answers

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1
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Choose the compound inequality that can be used to solve the original inequality |3x – 5| > 10.

A
–10 < |3x – 5| < 10
B
3x – 5 > –10 or 3x – 5 < 10
C
3x – 5 10
D
–10 < 3x – 5 < 10
2
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[6, –5][–5, 6](–5, 6)(6, –5)

A
[6, –5]
B
[–5, 6]
C
(–5, 6)
D
(6, –5)
3

Chose the graph that correctly illustrates the inequality.

Question illustration
A
Option
B
Option
C
Option
D
Option
4

{x|5 < x < 6}{x|–5 < x < 6}{x|x < 6} {x|–6 < x < 6}

A
{x|5 < x < 6}
B
{x|–5 < x < 6}
C
{x|x < 6}
D
{x|–6 < x < 6}
5

Identify the graph that correctly represents the inequality |x + 1| + 2 > 5.

A
Option
B
Option
C
Option
D
Option
6

Use the graph to determine the solution of the inequality |x + 1| + 2 > 5.(–4, 2)(0, 3)

A
Option
B
(–4, 2)
C
(0, 3)
D
Option
8

Check all of the following you included in your response.Both absolute values would need to be isolated first.You would need to write a compound inequality for each.Both compound inequalities would compare x – 1 to –15 and 15.The inequality with “ ” would use an “or” statement.

A
Both absolute values would need to be isolated first.
B
You would need to write a compound inequality for each.
C
Both compound inequalities would compare x – 1 to –15 and 15.
D
The inequality with “ ” would use an “or” statement.
9

Question text not available

Question illustration
A
Option
B
Option
C
Option
D
Option
10

Which graph accurately indicates the region, shaded in green, that would determine the solution for the inequality

A
Option
B
Option
12

Solve the inequality.

A
< 13
B
x < 27
C
13 < x < 27
D
–13 < x < 27
13

Express the answer in interval notation..[–9, –5] (–9, 5)

A
Option
B
[–9, –5]
C
(–9, 5)
D
Option

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