An airplane is flying in the direction of 30 degrees South of East at 500 mph. A wind is blowing in the direction of 45 degrees North of East at 55 mph. Find the direction angle of the airplane’s path, adjusted for the wind.

Resolve the plane’s velocity into east and north components: (500 cos 30°, −500 sin 30°) ≈ (433.0, −250.0) mph. The wind adds (55 cos 45°, 55 sin 45°) ≈ (38.9, 38.9) mph, giving a net velocity of about (471.9, −211.1) mph. This is 24.1° south of east, which is equivalent to 65.9° east of south, or S65.9°E: choice B.

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