What is h(x) = –3x2 – 6x + 5 written in vertex form?

Factor −3 from the terms involving x: h(x) = −3(x² + 2x) + 5. Since x² + 2x = (x + 1)² − 1, substitute and simplify: h(x) = −3[(x + 1)² − 1] + 5 = −3(x + 1)² + 8. Therefore, the vertex form is h(x) = −3(x + 1)² + 8, choice B.

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