Consider a circle whose equation is x2 + y2 + 4x – 6y – 36 = 0. Which statements are true? Check all that apply.

Move the constant to the right: x² + 4x + y² − 6y = 36. Completing the square for x² + 4x requires adding 4 to both sides, so B is true; the completed-square form is (x + 2)² + (y − 3)² = 49. The center is (−2, 3), making C true, and the radius is √49 = 7—not 6 or 49. A is false because you add 36 to both sides to move the constant.

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