How can you use a point on the graph of f –1(x) = 9x to determine a point on the graph of f(x) = log9x?

The functions f(x) = 9^x and f⁻¹(x) = log₉x are inverses. A point (a, b) on one function corresponds to the point (b, a) on the other, so switch the x- and y-coordinates. For example, (1, 9) on 9^x becomes (9, 1) on log₉x.

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