A 200 kg roller coaster car is located at the top of a hill where the height is 30 m. What is the velocity when it reaches the bottom of the hill?

Assuming the coaster’s gravitational potential energy becomes kinetic energy, use conservation of energy: mgh = ½mv². The mass cancels, so v = √(2gh) = √(2 × 9.8 × 30) ≈ 24.2 m/s. Therefore, the velocity is 24.2 m/s, choice D.

AI-written and checked against the verified answer.