Piecewise Defined Functions Answers

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1
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f(−10) = f(2) = f(−5) = f(−1) = f(8) =

Answers:
Part 1:-19
Part 2:4
Part 3:-9
Part 4:1
Part 5:-5
2
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3

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5

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7

What is the domain?

A
mc001-1.jpg
Option A
B
mc001-2.jpg
Option B
C
mc001-3.jpg
Option C
D
mc001-4.jpg
Option D
9

mc001-1.jpg

Question illustration
A
mc001-1.jpg
Option A
B
mc001-2.jpg
Option B
C
mc001-3.jpg
Option C
D
mc001-4.jpg
Option D
10

Which values of x are point(s) of discontinuity?

A
x = –6
B
x = –2
C
x = 0
D
x = 2
E
x = 4
11

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A
x = –4
B
x = –2
C
x = 0
D
x = 2
E
x = 4
12

a = b =

Answers:
Part 1:0
Part 2:2
13

Which statement is true for g(x)?

A
You can remove the discontinuity at x = 0 by defining g(0) = 0.
B
You can remove the discontinuity at x = 0 by defining g(0) = 2.
C
You can remove the discontinuity at x = 3 by defining g(3) = –1.
14

Compare and contrast the following piecewise defined functions.

Question illustration
Answer:

Both functions have the same domain – all real numbers except 0. Both functions are made up of linear and quadratic pieces on their domain. Neither function is continuous; f has jump discontinuity and g has point discontinuity. The range of f is y > 1 and the range of g is all real numbers except 2.

16

What is the range?

A
mc002-1.jpg
Option A
B
mc002-2.jpg
Option B
C
mc002-3.jpg
Option C
D
mc002-4.jpg
Option D
18

mc002-1.jpg

Question illustration
A
mc002-1.jpg
Option A
B
mc002-2.jpg
Option B
C
mc002-3.jpg
Option C
D
mc002-4.jpg
Option D
19

Which are removable discontinuities?

A
x = –2
B
x = –2 and x = 0
C
x = 0 and x = 4
D
x = –2, x = 0, and x = 4
20

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Answer not available

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