Identify the spectator ions in this reaction. Check all that apply.2H+ + CO32– + 2Na+ + 2OH– 2Na+ + CO32– + 2H2O

Spectator ions appear unchanged on both sides of the equation. CO₃²⁻ and Na⁺ are present on both sides, so they cancel when writing the net ionic equation. H⁺ and OH⁻ combine to form water, so they are not spectator ions.

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