AnswersCR CCSS Math 2 S2 M2960OXSolving for Side Lengths of Right Triangles

Solving for Side Lengths of Right Triangles Answers

12 verified answers
1
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Which equation could be used to solve for the length of XY?

A
XY = (22)sin(41°)
B
XY = (22)cos(41°)
C
XY =
Option C
D
XY =
Option D
2
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3

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Answer not available
6

A 25-foot long ladder is propped against a wall at an angle of 18° with the wall. Which diagram correctly represents this scenario?

A
[Image: A ladder is propped against a 25 foot tall wall. T...]
Option A
B
[Image: A 25 foot ladder is propped against a wall forming...]
Option B
C
[Image: A ladder is propped against a wall forming an 18 d...]
Option C
D
[Image: A 25 foot ladder is propped against a wall. The an...]
Option D
7

A 25-foot long ladder is propped against a wall at an angle of 18° with the wall. How high up the wall does the ladder reach? Round the answer to the nearest tenth of a foot.

A
13.8 ft
B
23.8 ft
C
26.3 ft
D
80.9 ft
8

Use the diagram to complete the statements. The measure of angle L is °. The trigonometric ratio that uses ∠M and LN to solve for NM is . The length of NM, to the nearest tenth, is approximately .

Answers:
Selection 1:70
Selection 2:tangent
Selection 3:57.7
9

sinecosine✔ tangent

Answer not available
10

7.622.3✔ 57.7

Answer not available
26

Which error did Kevin make?

A
He has the side lengths in the wrong place in the cosine ratio.
B
He multiplied both sides by the length of XZ instead of dividing by XZ.
C
He should have used the sine ratio.
D
He should have used the tangent ratio.
27

Which equations could be used to solve for the unknown lengths of △ABC? Check all that apply.

A
sin(45°) =
Option A
B
sin(45°) =
Option B
C
9 tan(45°) = AC
D
(AC)sin(45°) = BC
E
cos(45°) =
Option E
28

If Diana walks forward and her angle looking to the top of the building changes to 40°, how much closer is she to the building? Round the answer to the nearest tenth of a foot.

A
10.3 ft
B
17.6 ft
C
30.2 ft
D
97.2 ft
29

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