The width of Maya’s poster is 2 inches shorter than the length. The graph models the possible area (y) of Maya’s poster determined by its length (x).Which value of x makes sense for the length of Maya’s poster?

If the poster’s length is x inches, its width is x − 2 inches. For a real poster, both dimensions must be positive, so x − 2 > 0, which means x > 2. Therefore, the length must be greater than 2 inches, choice D.

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