Find the root(s) of f (x) = (x + 5)3(x - 9)2(x + 1).

A root occurs when one of the factors equals zero, and its multiplicity is the factor’s exponent. The factor (x + 5)³ gives x = -5 with multiplicity 3, while (x - 9)² gives x = 9 with multiplicity 2. The factor (x + 1) gives x = -1 with multiplicity 1.

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