Question 1 • Adv. Algebra II S1 Original
The first equation gives y = 5 − 2x. Dividing the second equation, 3y = 15 − 6x, by 3 gives the same rule: y = 5 − 2x. Choices A, B, and D each satisfy this rule; choice C does not, since when x = −2 the rule gives y = 9, not −9.
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