Binomial Distribution Answers

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1
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Question text not available

Answers:
Blank 1:0.246
Blank 2:0.015
2
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p represents the number of trials✔ probability of successnumber of successesprobability of failure.

A
number of trials
B
✔ probability of success
C
number of successes
D
probability of failure
3

k represents the number of trialsprobability of successnumber of successesprobability of failure.

A
number of trials
B
probability of success
C
number of successes
D
probability of failure
4

Question text not available

Answers:
Blank 1:10
Blank 2:0.5
Blank 3:5
5

p =

Answer:

0.5

6

k =

Answer:

5

7

What does each variable represent?n represents the . p represents the . k represents the .

Answers:
Selection 1:number of trials
Selection 2:probability of success
Selection 3:number of successes
12

Describe the pattern in the probability of getting greater numbers of successes.

Answer:

The probability decreases as the number of successes increases. For instance, the probability of getting 9 or 10 successes in 10 trials is very small and approaches 0 because such a high number of successes is very unlikely for this distribution.

13

Which of the following ideas did you include in your response? Check all of the boxes that apply.

A
The probability decreases as the number of successes increases.
B
The probability of 9 or 10 successes is very close to 0.
C
9 or 10 successes is very unlikely.
14

The distribution is

A
symmetric.
B
skewed.
C
both symmetric and skewed.
16

Which of the following ideas did you include in your response? Check all of the boxes that apply.

A
The number of trials affects the distribution.
B
5 successes is the expected value for 10 trials.
C
5 successes is close to an end of the distribution for 20 trials.
19

Explain why the second result is less.

Answer:

As the number of trials increases, the probability of getting exactly a specific number of successes that is far from the new mean decreases. For 10 trials with a 50% success rate, 5 is the expected value (mean) and has the highest probability. However, for 20 trials, the expected value is 10, and getting exactly 5 successes is much less likely because the distribution has spread out and centered around a higher value.

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