Suppose the probability of your hitting the bull’s-eye on a dartboard is 0.06. What is the probability of getting exactly two bull’s-eyes when you throw five darts?

Use the binomial probability for exactly 2 bull’s-eyes in 5 throws: choose which 2 throws hit, then multiply by the probabilities of 2 hits and 3 misses. This gives C(5,2) × 0.06² × 0.94³ = 10 × 0.0036 × 0.830584 ≈ 0.0299, so the best answer is 0.0299.

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