Question 5 • Mathematics for College Liberal Arts Sem 1 (1207350) BCPS 2025-26
The data have an upper quartile of 7 and an interquartile range of 4. The upper outlier fence is Q3 + 1.5 × IQR = 7 + 1.5 × 4 = 7 + 6 = 13. Since 12 is less than 13, it is not an outlier; this matches choice D.
AI-written and checked against the verified answer.