A coin is bent so that, when tossed, "heads” appears two-thirds of the time. What is the probability that more than 70% of 100 tosses result in "heads”?Find the z-table here.

For 100 tosses, the expected proportion of heads is 2/3, and the standard error is √[(2/3)(1/3)/100] ≈ 0.047. A proportion of 70% gives z = (0.70 − 2/3)/0.047 ≈ 0.707. The probability of getting more than 70% is the area to the right of this z-score, about 0.239, so the answer is 0.239.

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