A spinning top rotates so that its edge turns at a constant speed of 0.63 m/s. If the top has a radius of 0.10 m, what is the centripetal acceleration of the edge of the top?

Centripetal acceleration is calculated with a = v²/r. Using the edge speed of 0.63 m/s and radius of 0.10 m gives a = (0.63)²/0.10 = 3.969 m/s², which rounds to 4.0 m/s². Therefore, the correct choice is 4.0 m/s².

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