Centroid and Orthocenter Answers

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In the diagram, GB = 2x + 3..

Question illustration
A
5 units
B
10 units
C
15 units
D
30 units
5

A centroid is the intersection of three

A
altitudes in a triangle.
B
perpendicular bisectors in a triangle.
C
angle bisectors in a triangle.
D
medians in a triangle.
8

In which type of triangle is the orthocenter on the perimeter of the triangle?

A
a right triangle
B
an acute triangle
C
an obtuse triangle
D
an equilateral triangle
11

In triangle NQL, point S is the centroid, NS = (x + 10) feet, and SR = (x + 3) feet.

Question illustration
A
4 feet
B
7 feet
C
10 feet
D
14 feet
12

An orthocenter is the intersection of three

A
angle bisectors in a triangle.
B
altitudes in a triangle.
C
medians in a triangle.
D
perpendicular bisectors in a triangle.
15

In which figure is point G an orthocenter?

A
Triangle A B C is a right triangle. Lines are drawn from each point to the opposite side and intersect at point G.
Option A
B
Triangle F D E is shown. Lines are drawn from each point to the opposite side and intersect at point G. The lines cut each side into 2 equal parts.
Option B
C
Triangle L M N is shown. Lines are drawn from each point to the opposite side and intersect at point G. Each angle has a different measure.
Option C
D
Triangle H J K is shown. Lines are drawn from each point to the opposite side to form right angles and the lines intersect at point G.
Option D
16

Triangle A B C is shown. Lines are drawn from each point to the opposite side and intersect at point D.

Question illustration
A
Point D can be the orthocenter because it is the point of intersection of three segments coming from the vertices of the triangle.
B
Point D can be the orthocenter because each vertex angle appears to be bisected.
C
Point D cannot be the orthocenter because the orthocenter of an obtuse triangle is located outside the triangle.
D
Point D cannot be the orthocenter because the orthocenter of an obtuse triangle is located on the perimeter of the triangle.
17

Triangle H J K is shown. Lines are drawn from each point to the opposite side and intersect at point G to form line segments H C, J E, and K D.

Question illustration
A
Point G cannot be a centroid because JG does not equal GE.
B
Point G cannot be a centroid because JG and GE are in the ratio 1:2.
C
Point G can be a centroid because GE and JG are in the ratio 2:1.
D
Point G can be a centroid because JG + GE = JE.

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