Two spheres have volumes of 8 pi cm cubed and 64 pi cm cubed If the surface area of the smaller sphere is 16 pi cm squared , what is the surface area of the larger sphere?

The volume ratio is 64π ÷ 8π = 8, so the larger sphere’s radius is ∛8 = 2 times the smaller sphere’s radius. Surface area scales with the square of the radius, so it is 2² = 4 times as large: 16π × 4 = 64π cm². The correct choice is 64π cm².

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