Two spheres have volumes of 8π cm3 and 64π cm3. If the surface area of the smaller sphere is 16π cm2, what is the surface area of the larger sphere?

The volume ratio is 64π ÷ 8π = 8, so the larger sphere’s radius is ∛8 = 2 times the smaller sphere’s radius. Surface area scales with the square of the radius, so it is 2² = 4 times as large. Thus the larger surface area is 4 × 16π = 64π cm², choice A.

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