Question 19 • (OC27) GEO-1206310-S2-Degele-VOL7006P
Rain, wind, and sun reach the cylinder’s curved side and the hemisphere’s curved surface, but not the base on the ground or the surface where the two parts meet. The cylinder’s curved area is 2πrh = 2π(5)(40) = 400π square feet, and the hemisphere’s curved area is 2πr² = 2π(5²) = 50π square feet. Together, they have an exposed area of 450π square feet, choice A.
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