How would the vapor pressure of a solution that contains 0.5 mol of CaCl2 in 1.0 kg of water compare with the vapor pressure of a solution that contains 1.5 mol of glucose in 1.0 kg of water?

Vapor-pressure lowering depends on the number of dissolved particles. CaCl₂ produces about 3 ions per formula unit, so 0.5 mol CaCl₂ gives 0.5 × 3 = 1.5 mol of particles. Glucose does not dissociate, so 1.5 mol glucose gives 1.5 mol of particles. With the same amount of water, both solutions have the same vapor pressure, so the answer is “the same.”

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