Daniela recorded the low temperatures during the school day last week and this week. Her results are shown in the table. Low Temperatures during the School Day This Week and Last Week Low Temperatures This Week degree cap f 42 38 45 46 39 Low Temperatures Last Week degree cap f 56 58 52 62 62 Daniela used the steps below to find a relationship between the difference in the mean temperatures and the mean absolute deviations of the data sets. This Week Last Week Step 1 Find the mean. the fraction with numerator 42 plus 38 plus 45 plus 46 plus 39 and denominator 5 is equal to 42 Find the mean. the fraction with numerator 56 plus 58 plus 52 plus 62 plus 62 and denominator 5 is equal to 58 Step 2 Find the mean absolute deviation. the fraction with numerator start absolute value 42 minus 42 end absolute value plus start absolute value 38 minus 42 end absolute value plus start absolute value 45 minus 42 end absolute value plus start absolute value 46 minus 42 end absolute value plus start absolute value 39 minus 42 end absolute value and denominator 5 is equal to 2 point 8 Find the mean absolute deviation. the fraction with numerator start absolute value 56 minus 58 end absolute value plus start absolute value 58 minus 58 end absolute value plus start absolute value 52 minus 58 end absolute value plus start absolute value 62 minus 58 end absolute value plus start absolute value 62 minus 58 end absolute value and denominator 5 is equal to 3 point 2 Step 3 Find the ratio of the differences of the means compared to the mean absolute deviation. 42 over 2 point 8 is equal to 15 Find the ratio of the differences of the means compared to the mean absolute deviation. (58)/(3.2)=18.1⁢.25 Step 4 The difference in the means is about the fraction with numerator 15 plus 18 and denominator 2 is equal to 16 point 5 times the mean absolute deviations. In which step did Daniela make the first error?