What is the vertex of g of x is equal to 8 x squared minus 48 x plus 65 ?

For g(x) = 8x² − 48x + 65, the vertex’s x-coordinate is −b/(2a) = −(−48)/(2·8) = 3. Substituting x = 3 gives g(3) = 8(9) − 48(3) + 65 = −7. The vertex is (3, −7), which is choice D.

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