What is the vertex of g(x) = 8x2 – 48x + 65?

For a quadratic g(x) = ax² + bx + c, the vertex’s x-coordinate is −b/(2a). Here, a = 8 and b = −48, so x = 48/16 = 3. Substituting gives g(3) = 8(9) − 48(3) + 65 = −7, so the vertex is (3, −7), choice B.

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