AnswersFL-1200700-Mathematics for College Algebra MISSolving Quadratic Equations: Factoring

Completing The Square Answers

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1
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Solve for in the equation .

Question illustration
A
x = negative 7 plus-or-minus 4 StartRoot 6 EndRoot i
Option A
B
x = –7 ± 8i
C
x = 7 plus-or-minus 4 StartRoot 6 EndRoot i
Option C
D
x = 7 ± 8i
2
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Solve for in the equation .

Question illustration
A
x = 5 plus-or-minus 2 StartRoot 5 EndRoot
Option A
B
x = 5 plus-or-minus StartRoot 35 EndRoot
Option B
C
x = 10 plus-or-minus 2 StartRoot 5 EndRoot
Option C
D
x = 10 plus-or-minus StartRoot 35 EndRoot
Option D
3

Solve for in the equation .

Question illustration
A
x = –6 or x = 2
B
x = negative 2 plus-or-minus 2 StartRoot 2 EndRoot
Option B
C
x = –2 or x = 6
D
x = 2 plus-or-minus 2 StartRoot 2 EndRoot
Option D
4

Use completing the square to solve for in the equation .

Question illustration
A
x = –4 or 6
B
x = –2 or 14
C
x = 1 plus-or-minus StartRoot 89 EndRoot
Option C
D
x = 1 plus-or-minus StartRoot 87 EndRoot
Option D
5

Solve for in the equation .

Question illustration
A
x = –16 or x = –4
B
x = –10
C
x = –8
D
x = 4 or x = 16
6

Solve for in the equation .

Question illustration
A
x = negative 12 plus-or-minus StartRoot 85 EndRoot
Option A
B
x = negative 6 plus-or-minus StartRoot 23 EndRoot i
Option B
C
x = 6 plus-or-minus StartRoot 23 EndRoot i
Option C
D
x = 12 plus-or-minus StartRoot 85 EndRoot
Option D
7

Solve for in the equation .

Question illustration
A
x = negative 1 plus-or-minus StartRoot 15 EndRoot
Option A
B
x = negative 1 plus-or-minus StartRoot 17 EndRoot
Option B
C
x = negative 2 plus-or-minus 2 StartRoot 5 EndRoot
Option C
D
x = negative 1 plus-or-minus StartRoot 13 EndRoot
Option D
8

Solve for in the equation .

Question illustration
A
x = negative 6 plus-or-minus StartRoot 82 EndRoot
Option A
B
x = negative 6 plus-or-minus 2 StartRoot 17 EndRoot
Option B
C
x = 1 plus-or-minus StartRoot 33 EndRoot
Option C
D
x = 1 plus-or-minus StartRoot 47 EndRoot
Option D
9

Which value must be added to the expression x2 + x to make it a perfect-square trinomial?

A
One-fourth
Option A
B
One-half
Option B
C
1
D
4
10

Solve for in the equation .

Question illustration
A
x = five-halves plus-or-minus StartFraction StartRoot 29 EndRoot Over 2 EndFraction
Option A
B
x = five-halves plus-or-minus StartFraction StartRoot 41 EndRoot Over 4 EndFraction
Option B
C
x = five-fourths plus-or-minus StartFraction StartRoot 29 EndRoot Over 2 EndFraction
Option C
D
x = five-fourths plus-or-minus StartFraction StartRoot 41 EndRoot Over 4 EndFraction
Option D

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