What is the sum of square root of negative 2 and square root of negative 18 ?

For negative numbers, √(-a) = i√a. Thus √(-2) = i√2 and √(-18) = i√18 = 3i√2. Adding like terms gives i√2 + 3i√2 = 4i√2, so the answer is 4 i square root of 2.

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