Question 1 • Precalculus
Since h(x) = f(g(x)) and f(x) = 2x − 1, substitute g(x) into f to get h(x) = 2g(x) − 1. Set this equal to the given h(x): 2g(x) − 1 = (4/3)x − 1. Adding 1 and dividing by 2 gives g(x) = (2/3)x, which is choice A.
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