A bag contains one red pen, four black pens, and three blue pens. Two pens are randomly chosen from the bag and are not replaced.To the nearest hundredth, what is the probability that a black pen is chosen first and then another black pen is chosen?

There are 8 pens total, and 4 are black. The probability of choosing a black pen first is 4/8; after that, 3 black pens remain among 7 pens, so the probability of another black pen is 3/7. Multiply: (4/8)(3/7) = 3/14 ≈ 0.21, so the answer is 0.21.

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