AnswersFall 24 GMS Geometry Concepts and Connections BIndependent and Mutually Exclusive Events

Conditional Probability Answers

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1
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What statements are correct? Check all that apply.The conditional probability formula is P(X │ Y) = StartFraction P (X intersection Y) Over P (Y) EndFraction .The conditional probabilities P(D │ N) and P(N │ D) are equal for any events D and N.The notation P(R │ S) indicates the probability of event R, given that event S has already occurred.Conditional probability applies only to independent events.Conditional probabilities can be calculated using a Venn diagram.

Question illustration
A
The conditional probability formula is P(X │ Y) = .
Option A
B
The conditional probabilities P(D │ N) and P(N │ D) are equal for any events D and N.
C
The notation P(R │ S) indicates the probability of event R, given that event S has already occurred.
D
Conditional probability applies only to independent events.
E
Conditional probabilities can be calculated using a Venn diagram.
3

33/4733/6747/154✔ 80/154

A
33/47
B
33/67
C
47/154
D
✔ 80/154
4

47/80✔ 47/8747/15480/154

A
47/80
B
✔ 47/87
C
47/154
D
80/154
5

✔ no, P(male) does not equal P(male | geometry)no, P(male) equals P(male | geometry)yes, P(male) does not equal P(male | geometry)yes, P(male) equals P(male | geometry)

A
✔ no, P(male) does not equal P(male | geometry)
B
no, P(male) equals P(male | geometry)
C
yes, P(male) does not equal P(male | geometry)
D
yes, P(male) equals P(male | geometry)
7

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not replaced. Let event B be choosing a black ball first and event R be choosing a red ball second.

Answers:
P(B) =:8/12
P(R | B) =:4/11
P(B ∩ R) =:8/33
The probability that the first ball chosen is black and the second ball chosen is red is about percent.:24
8

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not replaced. Let event B be choosing a black ball first and event R be choosing a red ball second.

Answers:
P(B) =:8/12
P(R | B) =:4/11
P(B ∩ R) =:8/33
The probability that the first ball chosen is black and the second ball chosen is red is about percent.:24
9

4/8✔ 4/114/12

A
4/8
B
✔ 4/11
C
4/12
10

1/22/9✔ 8/33

A
1/2
B
2/9
C
✔ 8/33
11

22✔ 2450

A
22
B
✔ 24
C
50
14

Elias writes the numbers 1 through 20 on separate slips of paper. There are 16 white slips of paper and four yellow slips of paper. There are eight odd numbers on white slips, and the rest of the odd numbers are on yellow slips. Are the events "odd” and "yellow” independent?

A
no, because the probability of choosing a yellow slip is not equal to the probability of choosing a yellow slip given an odd number
B
no, because the probability of choosing an odd number is not equal to the probability of choosing an odd number on a yellow slip
C
yes, because the probability of choosing an odd number is equal to the probability of choosing an odd number given that the slip is yellow
D
yes, because the probability of choosing an odd number on a yellow slip of paper is equal to the probability of choosing an odd number
15

Which conditional probabilities are correct? Check all that apply.

A
P(D | F) =
Option A
B
P(E | D) =
Option B
C
P(D | E) =
Option C
D
P(F | E) =
Option D
E
P(E | F) =
Option E

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