The vertices of ΔABC are A(1,–2), B(1,1), and C(5,–2). Which could be the side lengths of a triangle that is similar but not congruent to ΔABC?

The side lengths of ΔABC are AB = 3, AC = 4, and BC = 5 units. A similar triangle must have all side lengths multiplied by the same scale factor. The lengths 9, 12, and 15 are each 3 times the original lengths, so they form a similar triangle; because the scale factor is not 1, it is not congruent.

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