The line x = 2 is the axis of symmetry for a parabola. The focus of the parabola is located 3 units from the vertex. Which could be the equation for the parabola?

A parabola with a vertical axis of symmetry x = 2 has standard form (x − 2)² = 4p(y − k), where its focus is |p| units from the vertex. Since that distance is 3, |p| = 3, so the coefficient 4p must be 12 or −12. Choice A has coefficient 12 and the required axis x = 2, so it could be the equation.

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