At 5 am in the morning, the outside temperature was 39° F. By 5 pm that same day, the outside temperature had increased by 43.59%. At 3 am the next day, the temperature had decreased by 25% of the temperature reading taken at 5 pm the previous day. Determine, with the given information, what the outside temperature was at 3 am the next day. Round your answer to the nearest degree.
First find the 5 pm temperature: 39 × 1.4359 = 56.0001°F, or about 56°F. A 25% decrease leaves 75% of that reading, so 56.0001 × 0.75 = 42.000075°F. Rounded to the nearest degree, the temperature was 42°F, choice d.
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