Cramer's Rule — Quiz Answers

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1
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Which equation can be used to determine x -value of the solution in the given system of linear equations? negative 2 x plus 14 y is equal to 148 3 x plus 5 y is equal to 246

A
the fraction with numerator the 2 by 2 matrix, row 1, column 1, negative 2 column 2, 148 row 2, column 1, 3 column 2, 246 and denominator the 2 by 2 matrix, row 1, column 1, negative 2 column 2, 14 row 2, column 1, 3 column 2, 5 is equal to 52
B
the fraction with numerator the 2 by 2 matrix row 1, 148 14 row 2, 246 5 and denominator the 2 by 2 matrix, row 1, column 1, negative 2 column 2, 14 row 2, column 1, 3 column 2, 5 is equal to 52
C
the fraction with numerator the 2 by 2 matrix, row 1, column 1, negative 2 column 2, 148 row 2, column 1, 3 column 2, 246 and denominator the 2 by 2 matrix, row 1, column 1, negative 2 column 2, 14 row 2, column 1, 3 column 2, 5 is equal to 18
D
the fraction with numerator the 2 by 2 matrix row 1, 148 14 row 2, 246 5 and denominator the 2 by 2 matrix, row 1, column 1, negative 2 column 2, 14 row 2, column 1, 3 column 2, 5 is equal to 18
2
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What is the 1 by 1 row matrix column 1 cap A sub x in the given system? 4 x minus y is equal to negative 3 negative 2 x plus y is equal to 5

A
the 2 by 2 matrix, row 1, column 1, negative 3 column 2, 5 row 2, column 1, negative 2 column 2, 1
B
the 2 by 2 matrix, row 1, column 1, 4 column 2, negative 1 row 2, column 1, negative 2 column 2, 1
C
the 2 by 2 matrix, row 1, column 1, negative 3 column 2, negative 1 row 2, column 1, 5 column 2, 1
D
the 2 by 2 matrix, row 1, column 1, 4 column 2, negative 3 row 2, column 1, negative 2 column 2, 5
4

Given the 2 by 2 matrix, row 1, column 1, 5 column 2, negative 4 row 2, column 1, 3 column 2, 6 the 2 by 1 column matrix x y is equal to the 2 by 1 column matrix 12 66 , what is the 1 by 1 row matrix column 1 cap A sub x ?

A
the 2 by 2 matrix row 1, 5 12 row 2, 3 66
B
the 2 by 2 matrix, row 1, column 1, 5 column 2, negative 4 row 2, column 1, 12 column 2, 66
C
the 2 by 2 matrix, row 1, column 1, 12 column 2, negative 4 row 2, column 1, 66 column 2, 6
D
the 2 by 2 matrix row 1, 12 66 row 2, 3 6
6

Given the 2 by 2 matrix, row 1, column 1, 12 column 2, negative 13 row 2, column 1, 17 column 2, negative 22 the 2 by 1 column matrix x y is equal to the 2 by 1 column matrix row 1 7 row 2 negative 51 , what is the 1 by 1 row matrix column 1 cap A sub y ?

A
the 2 by 2 matrix, row 1, column 1, 12 column 2, negative 13 row 2, column 1, 7 column 2, negative 51
B
the 2 by 2 matrix, row 1, column 1, 7 column 2, negative 51 row 2, column 1, 17 column 2, negative 22
C
the 2 by 2 matrix, row 1, column 1, 7 column 2, negative 13 row 2, column 1, negative 51 column 2, negative 22
D
the 2 by 2 matrix, row 1, column 1, 12 column 2, 7 row 2, column 1, 17 column 2, negative 51
7

Which determinants can be used to solve for x and y in the given system of linear equations? negative 3 x plus 2 y is equal to negative 9 4 x minus 15 y is equal to negative 25

A
the 1 by 1 row matrix cap A is equal to the 2 by 2 matrix, row 1, column 1, negative 3 column 2, 2 row 2, column 1, 4 column 2, negative 15 , start absolute value cap A sub x end absolute value is equal to the 2 by 2 matrix, row 1, column 1, negative 3 column 2, negative 9 row 2, column 1, 4 column 2, negative 25 , start absolute value cap A sub y end absolute value is equal to the 2 by 2 matrix, row 1, column 1, negative 9 column 2, 2 row 2, column 1, negative 25 column 2, negative 15
B
the 1 by 1 row matrix cap A is equal to the 2 by 2 matrix, row 1, column 1, negative 3 column 2, 2 row 2, column 1, 4 column 2, negative 15 , start absolute value cap A sub x end absolute value is equal to the 2 by 2 matrix, row 1, column 1, negative 9 column 2, 2 row 2, column 1, negative 25 column 2, negative 15 , start absolute value cap A sub y end absolute value is equal to the 2 by 2 matrix, row 1, column 1, negative 3 column 2, negative 9 row 2, column 1, 4 column 2, negative 25
C
the 1 by 1 row matrix cap A is equal to the 2 by 1 column matrix row 1 negative 9 row 2 negative 25 , start absolute value cap A sub x end absolute value is equal to the 2 by 2 matrix, row 1, column 1, negative 9 column 2, 2 row 2, column 1, negative 25 column 2, negative 15 , start absolute value cap A sub y end absolute value is equal to the 2 by 2 matrix, row 1, column 1, negative 3 column 2, negative 9 row 2, column 1, 4 column 2, negative 25
D
the 1 by 1 row matrix cap A is equal to the 2 by 1 column matrix row 1 negative 9 row 2 negative 25 , start absolute value cap A sub x end absolute value is equal to the 2 by 2 matrix, row 1, column 1, negative 3 column 2, negative 9 row 2, column 1, 4 column 2, negative 25 , start absolute value cap A sub y end absolute value is equal to the 2 by 2 matrix, row 1, column 1, negative 9 column 2, 2 row 2, column 1, negative 25 column 2, negative 15
9

Which system of linear equations can be solved using the given information? start absolute value cap A sub x end absolute value is equal to the 2 by 2 matrix, row 1, column 1, 20 column 2, negative 3 row 2, column 1, negative 192 column 2, 8 start absolute value cap A sub y end absolute value is equal to the 2 by 2 matrix, row 1, column 1, 2 column 2, 20 row 2, column 1, 12 column 2, negative 192

A
negative 3 x plus 8 y is equal to 20 2 x plus 12 y is equal to negative 192
B
20 x minus 3 y is equal to 2 negative 192 x plus 8 y is equal to 12
C
negative 3 x plus 2 y is equal to 20 8 x plus 12 y is equal to negative 192
D
2 x minus 3 y is equal to 20 12 x plus 8 y is equal to negative 192
10

What is the 1 by 1 row matrix column 1 cap A sub y in the given system of linear equations? negative 8 x plus y is equal to negative 6 3 x minus 2 y is equal to negative 1

A
the 2 by 2 matrix, row 1, column 1, negative 6 column 2, 1 row 2, column 1, negative 1 column 2, negative 2
B
the 2 by 2 matrix, row 1, column 1, negative 8 column 2, 1 row 2, column 1, negative 6 column 2, negative 1
C
the 2 by 2 matrix, row 1, column 1, negative 8 column 2, 1 row 2, column 1, 3 column 2, negative 2
D
the 2 by 2 matrix, row 1, column 1, negative 8 column 2, negative 6 row 2, column 1, 3 column 2, negative 1

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