If f(x) is an odd function, which statement about the graph of f(x) must be true?

An odd function satisfies f(−x) = −f(x) for every x in its domain. So whenever (x, f(x)) is on the graph, the point (−x, −f(x)) is also on it; these points are opposite each other across the origin. Therefore, the graph has rotational symmetry about the origin.

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