How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2? If necessary, round any values for the MAD to the nearest tenth to help answer the question. Set 1: 30, 25, 5, 32Set 2: 25, 30, 32

Set 1 has a mean of (30 + 25 + 5 + 32) ÷ 4 = 23, so its absolute deviations average (7 + 2 + 18 + 9) ÷ 4 = 9. Set 2 has a mean of (25 + 30 + 32) ÷ 3 = 29, so its absolute deviations average (4 + 1 + 3) ÷ 3 ≈ 2.7. The difference is 9 − 2.7 = 6.3, so the MAD of set 1 is 6.3 more than the MAD of set 2.

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