Question 26 • LHS Algebra I
One-quarter of 40 mL is 10 mL, so 10 mL is the 20% solution. The remaining three-quarters is 30 mL at concentration c. The total amount of acid is therefore 10(0.2) + 30c, and it must equal the acid in 40 mL of a 32% solution, 40(0.32). This gives 30c + 10(0.2) = 40(0.32), choice A.
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