A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acceleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground?h(t) = at2 + vt + h0

Use the height formula with a = −16, v = 60, and h₀ = 3: h(t) = −16t² + 60t + 3. The rocket reaches the ground when its height is 0, so solve −16t² + 60t + 3 = 0; the positive solution is about 3.80 seconds. The other solution is negative, so it does not represent a time after launch. The correct choice is 3.80 s.

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